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(Ózgertilgen ýaqyty 4 apta buryn)
Sýrma, qalaıy ıondaryn anyqtaý

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Sb (III) ıondary silti jáne amıak eritindilerimen metasýrma qyshqylynyń aq tústi tunbasyn túzedi:

H3[SbCl6] + 6 NaOH → Sb(OH)3↓ +6 NaCl + 3 H2O

3 H+ [SbCl6]3- + 6 OH-  → Sb(OH)3↓ +6 Cl- + 3 H2O

Tunba siltilerdiń artyq mólsherinde jáne kúshti qyshqyldyrda erıdi:

Sb(OH)3↓ + NaOH → Na[Sb(OH)4]

Sb(OH)3↓ + OH - → [Sb(OH)4]-

Reaksıanyń oryndalýy.

Sýrma (İİİ) tuzy eritindisiniń 2-3 tamshysyna 1-2 tamshy silti eritindisin qosyp, tunba túzilgenin baıqaý. Tunbany ekige bólip HCl jáne NaOH eritindilerinde eritý qajet.

Gıdrolız reaksıasy.

Sb(İİİ) tuzdarynyń suıytylǵan eritindileri, ásirese qyzdyran kezde gıdrolızdenedi. Reaksıa nátıjesinde aq tústi negizdik tuz – sýrmanyń(İİİ)- oksohlorıdi  SbOSİ túziledi:

Reaksıanyń oryndalýy.

SbCl3 + HOH ↔ SbOSİ ↓+ 2HCl

Sb3+ + Cl- + HOH ↔ SbOCl ↓ + 2 H+

SbO+  bir zarádti katıonnyń rolin atqarady. Tunba tuz qyshqylynda (ásirese qyzdyrǵanda) erıdi:  SbOCl ↓ + 2 HSİ+ Cl- ↔ SbCl4- + H2O .

Sýrma (İİİ) tuzy eritindisiniń 2-3 tamshysyna 5-6 tamshy dıstıldengen sý qosyp, býlandyrǵyshta qyzdyrý qajet.

Na2S2O3 áseri

Álsiz qyshqyl ortada sýrma (İİİ) tuzdary men natrıı tıosýlfatyn qyzdyrǵan kezde qyzyl tústi sýrma (İİİ) oksıdiniń dısýlfıdi tunbaǵa túsedi.

Reaksıanyń oryndalýy.

2 SbCl3 + 2 Na2S2O3 + 3 H2O → Sb2OS2↓ + 2 Na2SO4 + 6 HCl

2 Sb3+ + 2 S2O32- + 3 H2O → Sb2OS2↓ + 2 SO42- + 6 H+

Sýrma (İİİ) tuzy eritindisiniń 2-3 tamshysyna álsiz qyshqyldyq ortada 2-3 tamshy Na2S2O3 eritindisin qosyp, býlandyrǵyshta qyzdyrady.

H2S  áseri

Kúkirtti sýtek qyshqyldyq ortada sýrma (İİİ) ıondarymen ashyq qyzǵylt sary tústi amorfty  tunba túzedi.

Reaksıanyń oryndalýy.

2 SbCl3 + 3 H2S → Sb2S3 ↓ + 6 HCl

2 Sb 3+  + 3 H2S → Sb2S3 ↓ + 6 H+

Suıytylǵan beıtarap eritindilerden tústi koloıdty eritindi Sb2S3 túziledi. Sýrma (İİİ) sýlfıdi Na2S, (NH4)2S , (NH4)2S2 , NaOH eritindilerimen tıotuzdar beredi:

Reaksıanyń oryndalýy.

Sb2S3 +3 (NH4)2S → 2  (NH4)3Sb2S3

Sb2S3 +3 (NH4)2S2 → 2  (NH4)3SbS4 + S

Tıotuzdar turaqsyz qosylystar, olar tuz qyshqyldarynyń áserinen buzylady da, sýlfıd tunbaǵa túsedi:

Reaksıanyń oryndalýy.

2  (NH4)3SbS3 + 6 HCl → Sb2S3 ↓ + 3 H2S ↑ + 6 NH4Cl

Sýrma (İİİ) sýlfıdi 6 n. tuz qyshqyly eritindisinde erıdi (As2S3, As2As5 erimeıdi).

Reaksıanyń oryndalýy.

Sb2S3 + 6 HCl → 2 SbCl3 + 3 H2S ↑

Azot qyshqylymen nashar erıtin aq tústi HSbO3 túzedi:

Reaksıanyń oryndalýy.

3 Sb2S3 + 10 HNO3 → 6 HSbO3 ↓+ 9 S + 10 NO + 2 H2O

nemese:

Sb2S3 + 28 HNO3 → 2 HSbO3 ↓+ 3 H2SO4 + 28 NO2 + 10 H2O

 

                           Sb2S3 + 18 H2O – 28 e- → 2 HSbO3 + 3 SO42- + 34 H+                            1

                                          NO3- + 2 H + + 1 e-  → NO2 +  H2O                                         28

                                   __________________________________________________                                                 

                                   Sb2S3 + 28 NO3- + 22 H+ → 2 HSbO3 + SO42- + 28 NO2 + 10 H2O

Sb2S3, NH4OH jáne  (NH4)2CO3 eritindilerinde erimeıdi (myshák sýlfıdterinen aıyrmashylyǵy).

Reaksıanyń oryndalýy.

Sýrma (İİİ) tuzy eritindisiniń 4-5 tamshysyna 1-2 tamshy 2 n.  HCl eritindisin qosyp kúkirtti sýtek jiberý qajet. (Reaksıa sorǵysh shkafta oryndalady).

Derbes metaldarmen totyqsyzdandyrý

Kerneý qatarynda sýrmaǵa deıin ornalasqan metaldar ony bos kúıge deıin totyqsyzdandyrady:

Reaksıanyń oryndalýy.

2 H3[SbCl6] + 3 Sn → 2 Sb ↓ + 3 H2[SbCl4]

2 H3[SbCl6] + 3 Fe → 2 Sb ↓ + 3 FeCl2  +6 HCl

Sýrma (İİİ)- hlorıdi eritindisine bir túıirshik myrysh (ne temir shegesin) salyp bos sýrmanyń qara tunbasynyń túzilgenin baıqaýǵa bolady.


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